CÁLCULO GRACELI SINTÉTICO [71]

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ $\int {f(x)}dx=F(x)+C$ $G_{\mu \nu }\$ $T_{\mu \nu }$ $T^{\nu }{}_{\alpha }$ [DR] = ${\hat {H}}$ $\left|\psi ({\vec {r}},t)\right\rangle$ $F^{\mu \nu }$ $T^{\mu \nu }$ $P^{\mu }\!$ $-i\hbar {\frac {\partial }{\partial x_{n}}}$ $.$ = $\left|\psi ({\vec {r}},t)\right\rangle$

$b_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\sin nx)$ $G_{\mu \nu }\$ $T_{\mu \nu }$ $T^{\nu }{}_{\alpha }$ [DR] = ${\hat {H}}$ $\left|\psi ({\vec {r}},t)\right\rangle$ $F^{\mu \nu }$ $T^{\mu \nu }$ $P^{\mu }\!$ $-i\hbar {\frac {\partial }{\partial x_{n}}}$ $.$ = $\left|\psi ({\vec {r}},t)\right\rangle$

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ $\int {f(x)}dx=F(x)+C$ $\zeta (s)=\sum _{k=1}^{\infty }k^{-s}.$

$b_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\sin nx)$ $\int {f(x)}dx=F(x)+C$ $\zeta (s)=\sum _{k=1}^{\infty }k^{-s}.$

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ $\int {f(x)}dx=F(x)+C$ $F^{\mu \nu }$ $T^{\mu \nu }$ $P^{\mu }\!$

$b_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\sin nx)$ $\int {f(x)}dx=F(x)+C$ $F^{\mu \nu }$ $T^{\mu \nu }$ $P^{\mu }\!$

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ $G_{\mu \nu }\$ $T_{\mu \nu }$ $T^{\nu }{}_{\alpha }$ [DR] = ${\hat {H}}$ $\left|\psi ({\vec {r}},t)\right\rangle$ $F^{\mu \nu }$ $T^{\mu \nu }$ $P^{\mu }\!$ $-i\hbar {\frac {\partial }{\partial x_{n}}}$ $.$ = $\left|\psi ({\vec {r}},t)\right\rangle$

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ $\zeta (s)=\sum _{k=1}^{\infty }k^{-s}.$

$b_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\sin nx)$ $\zeta (s)=\sum _{k=1}^{\infty }k^{-s}.$

$a_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\cos nx)$ ${\partial f \over \partial {\bar {z}}}={1 \over 2}\left({\partial f \over \partial x}+i{\partial f \over \partial y}\right).$

$b_{n}={\frac {1}{\pi }}\delta x\sum _{n=1}^{\infty }(f(x)\sin nx)$ ${\partial f \over \partial {\bar {z}}}={1 \over 2}\left({\partial f \over \partial x}+i{\partial f \over \partial y}\right).$

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CÁLCULO GRACELI SINTÉTICO [71]

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